Optimization Problems#
From: https://mtk.sciml.ai/dev/tutorials/optimization/
2D Rosenbrock Function#
Wikipedia: https://en.wikipedia.org/wiki/Rosenbrock_function
Find \((x, y)\) that minimizes the loss function \((a - x)^2 + b(y - x^2)^2\)
using ModelingToolkit
using Optimization
using OptimizationOptimJL
Precompiling OptimizationMTKExt
Info Given OptimizationMTKExt was explicitly requested, output will be shown live
WARNING: Method definition AutoModelingToolkit() in module ADTypes at deprecated.jl:103 overwritten in module OptimizationMTKExt at /srv/juliapkg/packages/OptimizationBase/QZlI6/ext/OptimizationMTKExt.jl:9.
ERROR: Method overwriting is not permitted during Module precompilation. Use `__precompile__(false)` to opt-out of precompilation.
? OptimizationBase → OptimizationMTKExt
[ Info: Precompiling OptimizationMTKExt [ead85033-3460-5ce4-9d4b-429d76e53be9]
WARNING: Method definition AutoModelingToolkit() in module ADTypes at deprecated.jl:103 overwritten in module OptimizationMTKExt at /srv/juliapkg/packages/OptimizationBase/QZlI6/ext/OptimizationMTKExt.jl:9.
ERROR: Method overwriting is not permitted during Module precompilation. Use `__precompile__(false)` to opt-out of precompilation.
[ Info: Skipping precompilation since __precompile__(false). Importing OptimizationMTKExt [ead85033-3460-5ce4-9d4b-429d76e53be9].
@variables begin
x, [bounds = (-2.0, 2.0)]
y, [bounds = (-1.0, 3.0)]
end
@parameters a = 1 b = 1
Target (loss) function
loss = (a - x)^2 + b * (y - x^2)^2
The OptimizationSystem
@named sys = OptimizationSystem(loss, [x, y], [a, b])
MTK can generate Gradient and Hessian to solve the problem more efficiently.
u0 = [
x => 1.0
y => 2.0
]
p = [
a => 1.0
b => 100.0
]
prob = OptimizationProblem(sys, u0, p, grad=true, hess=true)
# The true solution is (1.0, 1.0)
sol = solve(prob, GradientDescent())
retcode: Success
u: 2-element Vector{Float64}:
1.0000000135463598
1.0000000271355158
Adding constraints#
OptimizationSystem(..., constraints = cons)
@variables begin
x, [bounds = (-2.0, 2.0)]
y, [bounds = (-1.0, 3.0)]
end
@parameters a = 1 b = 100
loss = (a - x)^2 + b * (y - x^2)^2
cons = [
x^2 + y^2 ≲ 1,
]
@named sys = OptimizationSystem(loss, [x, y], [a, b], constraints=cons)
u0 = [x => 0.14, y => 0.14]
prob = OptimizationProblem(sys, u0, grad=true, hess=true, cons_j=true, cons_h=true)
OptimizationProblem. In-place: true
u0: 2-element Vector{Float64}:
0.14
0.14
Use interior point Newton method for contrained optimization
solve(prob, IPNewton())
retcode: Success
u: 2-element Vector{Float64}:
0.7864151541684254
0.6176983125233897
Parameter estimation#
From: https://docs.sciml.ai/DiffEqParamEstim/stable/getting_started/
DiffEqParamEstim.jl
is not installed with DifferentialEquations.jl
. You need to install it manually:
using Pkg
Pkg.add("DiffEqParamEstim")
using DiffEqParamEstim
The key function is DiffEqParamEstim.build_loss_objective()
, which builds a loss (objective) function for the problem against the data. Then we can use optimization packages to solve the problem.
Estimate a single parameter from the data and the ODE model#
Let’s optimize the parameters of the Lotka-Volterra equation.
using DifferentialEquations
using Plots
using DiffEqParamEstim
using ForwardDiff
using Optimization
using OptimizationOptimJL
# Example model
function lotka_volterra!(du, u, p, t)
du[1] = dx = p[1] * u[1] - u[1] * u[2]
du[2] = dy = -3 * u[2] + u[1] * u[2]
end
u0 = [1.0; 1.0]
tspan = (0.0, 10.0)
p = [1.5] ## The true parameter value
prob = ODEProblem(lotka_volterra!, u0, tspan, p)
sol = solve(prob, Tsit5())
[ Info: Precompiling IJuliaExt [2f4121a4-3b3a-5ce6-9c5e-1f2673ce168a]
retcode: Success
Interpolation: specialized 4th order "free" interpolation
t: 34-element Vector{Float64}:
0.0
0.0776084743154256
0.23264513699277584
0.4291185174543143
0.6790821987497083
0.9444046158046306
1.2674601546021105
1.6192913303893046
1.9869754428624007
2.2640902393538296
2.5125484290863063
2.7468280298123062
3.0380065851974147
⋮
6.455762090996754
6.780496138817711
7.171040059920871
7.584863345264154
7.978068981329682
8.48316543760351
8.719248247740158
8.949206788834692
9.200185054623292
9.438029017301554
9.711808134779586
10.0
u: 34-element Vector{Vector{Float64}}:
[1.0, 1.0]
[1.0454942346944578, 0.8576684823217128]
[1.1758715885138271, 0.6394595703175443]
[1.419680960717083, 0.4569962601282089]
[1.8767193950080012, 0.3247334292791134]
[2.588250064553348, 0.26336255535952197]
[3.860708909220769, 0.2794458098285261]
[5.750812667710401, 0.522007253793458]
[6.8149789991301635, 1.9177826328390826]
[4.392999292571394, 4.1946707928506015]
[2.1008562663496537, 4.316940492484671]
[1.2422757654297416, 3.1073646247560602]
[0.9582720921023415, 1.7661433892230267]
⋮
[0.9522065255261748, 1.438344843391383]
[1.100462377627641, 0.752662073076037]
[1.5991134291557731, 0.39031816752231707]
[2.6142539677883248, 0.26416945387526314]
[4.24107612719179, 0.3051236762922018]
[6.791123785297775, 1.1345287797146668]
[6.26537067576476, 2.741693507540315]
[3.780765111887945, 4.431165685863443]
[1.816420140681737, 4.064056625315896]
[1.1465021407690763, 2.791170661621642]
[0.9557986135403417, 1.623562295185047]
[1.0337581256020802, 0.9063703842885995]
Create a sample dataset with some noise.
ts = range(tspan[begin], tspan[end], 200)
data = [sol.(ts, idxs=1) sol.(ts, idxs=2)] .* (1 .+ 0.03 .* randn(length(ts), 2))
200×2 Matrix{Float64}:
1.0075 0.990606
0.96939 0.948962
1.06264 0.82398
1.1006 0.769309
1.16964 0.649704
1.22061 0.637688
1.2782 0.523885
1.33998 0.521352
1.36494 0.463601
1.38911 0.478422
1.60868 0.411664
1.60411 0.382213
1.71605 0.356637
⋮
1.17493 2.63616
1.06993 2.52247
0.999327 2.28003
0.97692 2.07856
1.00545 1.895
0.988272 1.725
0.973178 1.57529
0.96801 1.32893
0.918543 1.29198
1.0292 1.08628
0.978575 1.00688
1.0063 0.949827
Plotting the sample dataset and the true solution.
plot(sol)
scatter!(ts, data, label=["u1 data" "u2 data"])
DiffEqParamEstim.build_loss_objective()
builds a loss function for the ODE problem for the data.
We will minimize the mean squared error using L2Loss()
.
Note that
the data should be transposed.
Uses
AutoForwardDiff()
as the automatic differentiation (AD) method since the number of parameters plus states is small (<100). For larger problems, one can useOptimization.AutoZygote()
.
alg = Tsit5()
cost_function = build_loss_objective(
prob, alg,
L2Loss(collect(ts), transpose(data)),
Optimization.AutoForwardDiff(),
maxiters=10000, verbose=false
)
plot(
cost_function, 0.0, 10.0,
linewidth=3, label=false, yscale=:log10,
xaxis="Parameter", yaxis="Cost", title="1-Parameter Cost Function"
)
There is a dip (minimum) in the cost function at the true parameter value (1.5). We can use an optimizer, e.g., Optimization.jl
, to find the parameter value that minimizes the cost. (1.5 in this case)
optprob = Optimization.OptimizationProblem(cost_function, [1.42])
optsol = solve(optprob, BFGS())
retcode: Success
u: 1-element Vector{Float64}:
1.4999806364993953
The fitting result:
newprob = remake(prob, p=optsol.u)
newsol = solve(newprob, Tsit5())
plot(sol)
plot!(newsol)
Estimate multiple parameters#
Let’s use the Lotka-Volterra (Fox-rabbit) equations with all 4 parameters free.
function f2(du, u, p, t)
du[1] = dx = p[1] * u[1] - p[2] * u[1] * u[2]
du[2] = dy = -p[3] * u[2] + p[4] * u[1] * u[2]
end
u0 = [1.0; 1.0]
tspan = (0.0, 10.0)
p = [1.5, 1.0, 3.0, 1.0] ## True parameters
alg = Tsit5()
prob = ODEProblem(f2, u0, tspan, p)
sol = solve(prob, alg)
retcode: Success
Interpolation: specialized 4th order "free" interpolation
t: 34-element Vector{Float64}:
0.0
0.0776084743154256
0.23264513699277584
0.4291185174543143
0.6790821987497083
0.9444046158046306
1.2674601546021105
1.6192913303893046
1.9869754428624007
2.2640902393538296
2.5125484290863063
2.7468280298123062
3.0380065851974147
⋮
6.455762090996754
6.780496138817711
7.171040059920871
7.584863345264154
7.978068981329682
8.48316543760351
8.719248247740158
8.949206788834692
9.200185054623292
9.438029017301554
9.711808134779586
10.0
u: 34-element Vector{Vector{Float64}}:
[1.0, 1.0]
[1.0454942346944578, 0.8576684823217128]
[1.1758715885138271, 0.6394595703175443]
[1.419680960717083, 0.4569962601282089]
[1.8767193950080012, 0.3247334292791134]
[2.588250064553348, 0.26336255535952197]
[3.860708909220769, 0.2794458098285261]
[5.750812667710401, 0.522007253793458]
[6.8149789991301635, 1.9177826328390826]
[4.392999292571394, 4.1946707928506015]
[2.1008562663496537, 4.316940492484671]
[1.2422757654297416, 3.1073646247560602]
[0.9582720921023415, 1.7661433892230267]
⋮
[0.9522065255261748, 1.438344843391383]
[1.100462377627641, 0.752662073076037]
[1.5991134291557731, 0.39031816752231707]
[2.6142539677883248, 0.26416945387526314]
[4.24107612719179, 0.3051236762922018]
[6.791123785297775, 1.1345287797146668]
[6.26537067576476, 2.741693507540315]
[3.780765111887945, 4.431165685863443]
[1.816420140681737, 4.064056625315896]
[1.1465021407690763, 2.791170661621642]
[0.9557986135403417, 1.623562295185047]
[1.0337581256020802, 0.9063703842885995]
ts = range(tspan[begin], tspan[end], 200)
data = [sol.(ts, idxs=1) sol.(ts, idxs=2)] .* (1 .+ 0.01 .* randn(length(ts), 2))
200×2 Matrix{Float64}:
0.993944 1.00923
1.04943 0.905931
1.06434 0.825564
1.09298 0.751623
1.15848 0.665119
1.1828 0.604523
1.25912 0.564418
1.3203 0.515813
1.38326 0.472359
1.44395 0.439597
1.54774 0.409588
1.62797 0.382154
1.75139 0.357456
⋮
1.13863 2.74207
1.06917 2.47146
1.01348 2.23927
0.996268 2.0415
0.960085 1.86934
0.973949 1.68103
0.966104 1.52953
0.956521 1.38042
0.967096 1.22825
0.980978 1.09541
1.01245 0.990564
1.03031 0.916831
Then we can find multiple parameters at once using the same steps. True parameters are [1.5, 1.0, 3.0, 1.0]
.
cost_function = build_loss_objective(
prob, alg, L2Loss(collect(ts), transpose(data)),
Optimization.AutoForwardDiff(),
maxiters=10000, verbose=false
)
optprob = Optimization.OptimizationProblem(cost_function, [1.3, 0.8, 2.8, 1.2])
result_bfgs = solve(optprob, BFGS())
retcode: Success
u: 4-element Vector{Float64}:
1.4867686870113674
0.992093127957304
3.0362558507702277
1.0143641137951283
This notebook was generated using Literate.jl.